A ___________ adhesive is best suited for long-term mounting for photographs
a. Rubber Cement
b. Spray Adhesive
c. Dry Mounting
d. Hot glue stick
A device used to assist in free-hand tracing original artwork is a
a. Light table
b. Template
c. Scanner
d. Photocopier
Which cutting tool is most accurate when cutting illustration board
a. X-acto
b .Matt Cutter
c. Cutting Board
d. Scissors
Easy 10 points?
A.
C.
C.
Reply:A. Rubber Cement
A. Light Table
B. Matt cutter (as in rotary cutter with mat)
Reply:A
A
B
Reply:c
a
b
Sunday, July 12, 2009
I need to prepare a legal document that requires a former employee to return all digitalized property of the c
I need to find/prepare a legal document that requires the signee, a former employee, to return all Digitalized assets of the company that he/she has retained on her personal computer in the course of working from home. I was looking around to find a similar form or template online and any help would be greatly appreciated,
I need to prepare a legal document that requires a former employee to return all digitalized property of the c
Unfortunately, you're probably out of luck if your dealing with a former employee. If you want your data/project back now, you'll have to sue them if they won't give it back willingly.
The best time to be thinking about the property/data rights of the company is at the time when you're in the process of hiring someone and this needs to be explained and agreed to before they start working for you.
I need to prepare a legal document that requires a former employee to return all digitalized property of the c
Unfortunately, you're probably out of luck if your dealing with a former employee. If you want your data/project back now, you'll have to sue them if they won't give it back willingly.
The best time to be thinking about the property/data rights of the company is at the time when you're in the process of hiring someone and this needs to be explained and agreed to before they start working for you.
Will this graphic card work on my computer? (I'm trying to play C&C3)?
I have a HP model a1720n
http://www.shopping.hp.com/webapp/shoppi...
This is the required graphics card: 64 MB GeForce3-class video card. The game only officially supports cards with ATI (Radeon 8500 or greater) and Nvidia chipsets, and the Intel GMA 900 and GMA 950 products. The GeForce 4 MX is not supported
I'm thinking about getting 3DFuzion GeForce 6200 LE PCI-E Video Card:
http://www.circuitcity.com/ssm/3DFuzion-...
Will this graphic card work on my computer? (I'm trying to play C%26amp;C3)?
I just checked the complete specs and you're in luck, the a1720n does have a PC-Express x16 slot. But do NOT get that card, it's garbage. In fact, avoid any Nvidia card models with the letters LE following the number, those are the worst versions you can find.
For recent Geforce cards: LE=bad, GS=ok, GT=better, GTX=best
For a good budget card, get the GeForce 7300GT- you spend $15 more initially but there's a $25 rebate on NewEgg, so in the end it actually costs less...
Reply:For decent performance(medium) I recommend a 7300 gt ddr2(roughly=to a 6600 gt although the (7300gt)ddr 3 version feels like a different significantly faster card) But since you have a C2D I recommend a 8600 gt(high settings) or if you have the money and want high resolution max everything quality get a 8800 gts/gtx/hd 2900 xt(you might as well get another gigabyte and OverClock that C2D as thats the main reason why their better than AMDs as if you don't their equal)
DO NOT EVER GET A _200 SERIES NVIDIA THEY ARE NOT FOR GAMING JUST INTEGRATED GRAPHICS EQUIVALENT OF THE SAME GENERATION.
Reply:i dont think ur machine has a pci-e slot .. but if it does get somthing like a nvidia 7800 .. i think ur choice is too low ...
Reply:Assuming you DO have a pci-e slot on the motherboard, yes that card will work, but a 6200, or any 6 series, is now extremely outdated, the 8 series is out and the 9 series is to be announced within the year. At minimum a 7600gt would perform good out of the box..
http://www.shopping.hp.com/webapp/shoppi...
This is the required graphics card: 64 MB GeForce3-class video card. The game only officially supports cards with ATI (Radeon 8500 or greater) and Nvidia chipsets, and the Intel GMA 900 and GMA 950 products. The GeForce 4 MX is not supported
I'm thinking about getting 3DFuzion GeForce 6200 LE PCI-E Video Card:
http://www.circuitcity.com/ssm/3DFuzion-...
Will this graphic card work on my computer? (I'm trying to play C%26amp;C3)?
I just checked the complete specs and you're in luck, the a1720n does have a PC-Express x16 slot. But do NOT get that card, it's garbage. In fact, avoid any Nvidia card models with the letters LE following the number, those are the worst versions you can find.
For recent Geforce cards: LE=bad, GS=ok, GT=better, GTX=best
For a good budget card, get the GeForce 7300GT- you spend $15 more initially but there's a $25 rebate on NewEgg, so in the end it actually costs less...
Reply:For decent performance(medium) I recommend a 7300 gt ddr2(roughly=to a 6600 gt although the (7300gt)ddr 3 version feels like a different significantly faster card) But since you have a C2D I recommend a 8600 gt(high settings) or if you have the money and want high resolution max everything quality get a 8800 gts/gtx/hd 2900 xt(you might as well get another gigabyte and OverClock that C2D as thats the main reason why their better than AMDs as if you don't their equal)
DO NOT EVER GET A _200 SERIES NVIDIA THEY ARE NOT FOR GAMING JUST INTEGRATED GRAPHICS EQUIVALENT OF THE SAME GENERATION.
Reply:i dont think ur machine has a pci-e slot .. but if it does get somthing like a nvidia 7800 .. i think ur choice is too low ...
Reply:Assuming you DO have a pci-e slot on the motherboard, yes that card will work, but a 6200, or any 6 series, is now extremely outdated, the 8 series is out and the 9 series is to be announced within the year. At minimum a 7600gt would perform good out of the box..
Designing a Binary Search Tree in C++ ?
Design a class template Table as the table to store the information of the people and another class Person to represent each individual person of the people in a table. The data structure of a table is the pointer-based binary search tree (BST). A table of people is an object of the class Table. The information of each person is store in a node, which is an object of the class Person. A relational database is conceptually a collection of tables (files). A table is abstractly a collection of to records (attributes).The information of a person consists of her (his) name, sex (male or female), birthday, address, city and phone number. Assume the names of the people are unique. The search key is the person’s name. Our program should be able to save a table for use later. We should be able to retrieve the information of a subgroup of people based on a given criterion. I need Add , Print , Delete and Save functions.
Designing a Binary Search Tree in C++ ?
Yeah, please leave Computer Science. You'll never be any good at it, since you don't do your own work. The world doesn't need people like you writing software for Air Traffic Control, radiation therapy machines, or even financial institutions. Do us all a favor and become a hair stylist. The worst that will happen there is that you give someone a bad haircut.
Reply:Do your own homework... your not asking a question your asking someone to do it all for you...
wedding floral centerpieces
Designing a Binary Search Tree in C++ ?
Yeah, please leave Computer Science. You'll never be any good at it, since you don't do your own work. The world doesn't need people like you writing software for Air Traffic Control, radiation therapy machines, or even financial institutions. Do us all a favor and become a hair stylist. The worst that will happen there is that you give someone a bad haircut.
Reply:Do your own homework... your not asking a question your asking someone to do it all for you...
wedding floral centerpieces
Can someone look over my C++ function?
Hey guys just want to bounce my algorithm of someone else to see if what I am thinking is correct.
I have a binary tree and I want to swap the sub trees of the tree. So my root node is called "root". The root node is made up of basically a variable to hold the data and a left pointer "llink" that points to the left subtree and a right pointer "rlink" that points to the right subtree.
Ok so my function is here:
template%26lt;class elemType%26gt;
void binaryTreeType%26lt;elemType%26gt;::swapSubTrees
{
nodeType Temp;
Temp = new nodeType;
Temp = root-%26gt;llink;
root-%26gt;llink = root-%26gt;rlink;
root-%26gt;rlink = Temp;
delete Temp;
}
Does this function look like it will accomplish what I want it to do?? The reason I dont test it out myself is because I have to write all the other functions for the tree but I just wanted to make sure that this works first,
Thanks!
Can someone look over my C++ function?
well, the best way to test it is to write a small test function which just uses this function, and afterwards you check the result. this is called a unittest, and it's a great concept, because you can run this test whenever you changed the code, and always can be sure that this function still works.
anyway, it's not ok. first of all, root-%26gt;llink or root-%26gt;rlink can be NULL, and then you should swap a NULL pointer, and not an allocated object.
also, nodeType must be a pointer, otherwise you can't allocate it with new.
also, you delete Temp (in the last line of the function), which means that root-%26gt;rlink is deleted, because root-%26gt;rlink points to Temp.
also, i just saw that you're actually allocating new objects, but that's not necessary.
the correct code would be this (assuming that nodeType is a pointer):
nodeType Temp=root-%26gt;llink;
root-%26gt;llink=root-%26gt;rlink;
root-%26gt;rlink=Temp;
that should be enough. or just use std::swap (in %26lt;algorithm%26gt;), which basically does the same.
Reply:yes it will work
I have a binary tree and I want to swap the sub trees of the tree. So my root node is called "root". The root node is made up of basically a variable to hold the data and a left pointer "llink" that points to the left subtree and a right pointer "rlink" that points to the right subtree.
Ok so my function is here:
template%26lt;class elemType%26gt;
void binaryTreeType%26lt;elemType%26gt;::swapSubTrees
{
nodeType Temp;
Temp = new nodeType;
Temp = root-%26gt;llink;
root-%26gt;llink = root-%26gt;rlink;
root-%26gt;rlink = Temp;
delete Temp;
}
Does this function look like it will accomplish what I want it to do?? The reason I dont test it out myself is because I have to write all the other functions for the tree but I just wanted to make sure that this works first,
Thanks!
Can someone look over my C++ function?
well, the best way to test it is to write a small test function which just uses this function, and afterwards you check the result. this is called a unittest, and it's a great concept, because you can run this test whenever you changed the code, and always can be sure that this function still works.
anyway, it's not ok. first of all, root-%26gt;llink or root-%26gt;rlink can be NULL, and then you should swap a NULL pointer, and not an allocated object.
also, nodeType must be a pointer, otherwise you can't allocate it with new.
also, you delete Temp (in the last line of the function), which means that root-%26gt;rlink is deleted, because root-%26gt;rlink points to Temp.
also, i just saw that you're actually allocating new objects, but that's not necessary.
the correct code would be this (assuming that nodeType is a pointer):
nodeType Temp=root-%26gt;llink;
root-%26gt;llink=root-%26gt;rlink;
root-%26gt;rlink=Temp;
that should be enough. or just use std::swap (in %26lt;algorithm%26gt;), which basically does the same.
Reply:yes it will work
Data Grid in ASP.Net(C#)?
I was binding data to the data grid from database.I'm using 3 template coulmns for edit,view n delete property.I'm writing the code for do this operations.But it didn't work.The following is the code that I'm using.
private void dgjobs_ItemCommand(object sender,DataGridCommandEventArgs e)
{
switch(e.CommandName)
{
case "Select":
Response.Redirect("Job Posting.aspx?id=" +dgjobs.DataKeys[e.Item.ItemIndex].ToStr...
break;
case "Delete":
SQL.NonQuery("DeleteJob "+dgjobs.DataKeys[e.Item.ItemIndex].ToSt...
dgjobs.DataSource=SQL.SQLTable("S... " + Session["cid"].ToString());
dgjobs.DataBind();
break;
case "View":
{
Response.Redirect("ViewPosting.as...
break;
}
}
}
Will you help me?
Data Grid in ASP.Net(C#)?
Your code is not displaying correctly above.
You didn't specify whats the problem.
You can figure it out by yourself through debugging your code flow of control.
click next to to your switch statement. Press F9. This creates a break point. Run your page under debug mode (through pressing F5). The execution stops at your break point. place the pointer over your variables to see their values. Press F10 to step through your code. That's how you debug your page!
private void dgjobs_ItemCommand(object sender,DataGridCommandEventArgs e)
{
switch(e.CommandName)
{
case "Select":
Response.Redirect("Job Posting.aspx?id=" +dgjobs.DataKeys[e.Item.ItemIndex].ToStr...
break;
case "Delete":
SQL.NonQuery("DeleteJob "+dgjobs.DataKeys[e.Item.ItemIndex].ToSt...
dgjobs.DataSource=SQL.SQLTable("S... " + Session["cid"].ToString());
dgjobs.DataBind();
break;
case "View":
{
Response.Redirect("ViewPosting.as...
break;
}
}
}
Will you help me?
Data Grid in ASP.Net(C#)?
Your code is not displaying correctly above.
You didn't specify whats the problem.
You can figure it out by yourself through debugging your code flow of control.
click next to to your switch statement. Press F9. This creates a break point. Run your page under debug mode (through pressing F5). The execution stops at your break point. place the pointer over your variables to see their values. Press F10 to step through your code. That's how you debug your page!
You want to make an isometric drawing of a 1/2 in diameter sphere. What size circle template should you use?
A) 7/16 in B) 1/2 in C) 9/16 in D) 5/8 in
You want to make an isometric drawing of a 1/2 in diameter sphere. What size circle template should you use?
Well, I would use B) 1/2 in.
These questions where the answer sees so obvious tend to make me have second thoughts, but I can't see why it wouldn't be B) for a sphere, of course a circle on one of the orthogonal axises would be drawn as an ellipse.
Reply:A sphere in an isometric drawing is 1.2246 times the diameter. That is because isometric use a scale that is actually larger than life. This requires 5/8 diameter template.
Reply:Assuming the circle template is labelled properly, then the answer would be 1/2". If it wasn't labelled at all, you couldn't use the one that was 1/2" wide or tall because isometric is a distorted 2D view of an object in 3D. There is no true scale for isometrically drawing objects...only the scale used the along its axes (also see axonometric projection).
P.S., although the previous poster is technically correct in what they intend to mean. A proper template should label its features by intended depiction size and not actual drawn size.
You want to make an isometric drawing of a 1/2 in diameter sphere. What size circle template should you use?
Well, I would use B) 1/2 in.
These questions where the answer sees so obvious tend to make me have second thoughts, but I can't see why it wouldn't be B) for a sphere, of course a circle on one of the orthogonal axises would be drawn as an ellipse.
Reply:A sphere in an isometric drawing is 1.2246 times the diameter. That is because isometric use a scale that is actually larger than life. This requires 5/8 diameter template.
Reply:Assuming the circle template is labelled properly, then the answer would be 1/2". If it wasn't labelled at all, you couldn't use the one that was 1/2" wide or tall because isometric is a distorted 2D view of an object in 3D. There is no true scale for isometrically drawing objects...only the scale used the along its axes (also see axonometric projection).
P.S., although the previous poster is technically correct in what they intend to mean. A proper template should label its features by intended depiction size and not actual drawn size.
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